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Syntax error unexpected dbname t variable

$ conn) { die( ' Not connected : '. mysql_ error( ) ) ; } $ db_ selected = mysql_ select_ db( $ dbName, $ conn) ; if (! $ db_ selected) { die ( ' Can\ ' t use. ksort( fruits) ; ここに$ が無いせいで起こっているエラーではないかと思われます。 「 PHP Parse error: syntax error, unexpected T_ VARIABLE in」 というエラーは、 記号の入力 ミスであったりカッコやダブルクォーテーションの閉じ忘れだったり. current = explode( ", ", $ keywords[ 0] ) ;. You' re missing an extra comma. There is no semicolon at the end of that instruction causing the error. Like RiverC pointed out, there is no semicolon at the end of the previous line! require ( " scripts/ connect. It seems you have no- semicolons. PHP parse/ syntax errors; and how to solve them? I am getting the following error in the quote function: Parse error: syntax error, unexpected ' $ value ' ( T_ VARIABLE) in D: \ xampp\ htdocs\ fizzy\ submit. Parse error: syntax error, unexpected ' " ', expecting identifier ( T_ STRING) or variable ( T_ VARIABLE) or number ( T_ NUM_ STRING) in C: \ xampp\ htdocs\ test.

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  • Video:Variable error syntax

    Unexpected syntax variable

    line NN と出るからといって、 29 行目に問題があるとは限り. In line 54 ( where the error is occurring). echo $ _ SESSION[ loggedon] ;. echo $ _ SESSION[ ' loggedon' ] ;. which means you forgot to include ' in the session value. You should always include single quotes unless the. Use print_ r( ) in this way, foreach( $ stmt as $ Contrato) { print_ r ( $ Contrato- > getDatosContrato( ) ) ; echo ' < br / > ' ; }. Your code has some weird characters after the semicolon of this line: $ section1- > execute( ) ; ​ $ section2- > execute( ) ; ​ / / same for this line. If you look into a hex editor you see this: f 6e 31 2d 3e. Parse error: syntax error, unexpected ' $ _ POST' ( T_ VARIABLE) in C: \ xampp\ htdocs\ yomi\ admin\ update. $ username, $ password, $ dbname) ; / / Check connection if ( $ conn- > connect_ error) { die( " Connection failed: ".